find the mass of a hollow sphere of metal having internal and external diameter of 20 cm and 22 cm given 1 cube cm of metal has a mass of 21 g
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Given,
Internal radius (r)=20/2
10 Cm
External radius (R) = 22/2
=11cm
We know,
4/3Ο((R*R)-(r*r)Cm cube
= 4/3*22/7*(121-100)
= 4/3*22/7*21
=4/3*22*3
= 4*22
= 88 cm cube
1 cube cm = 21gm
Then,
88 cube cm = 21*88gm
=1848 gm
Internal radius (r)=20/2
10 Cm
External radius (R) = 22/2
=11cm
We know,
4/3Ο((R*R)-(r*r)Cm cube
= 4/3*22/7*(121-100)
= 4/3*22/7*21
=4/3*22*3
= 4*22
= 88 cm cube
1 cube cm = 21gm
Then,
88 cube cm = 21*88gm
=1848 gm
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