Question

Find the mass of a piece of iron that occupies a volume of 250cm3 , given that the density of iron is 7.8 g/cm3 .

Answer 1

Answer:

Given that : Volume = 250cm3

Density = 7.8 g/cm3

Therefore, Mass = Density × Volume

= (7.8 × 250) g

= 1950.0 g

= 1950 g .

Answer 2

Answer:

The mass of a piece of iron is equal to 1950g which occupies volume 250cm³ and density equals to 7.8gcm⁻³.

Explanation:

Given: The Density of the iron is equal to 7.8gcm⁻³.

The volume occupied by piece of iron, $V=250cm^{3}$

Consider that m is the mass of the iron piece.

Density is given by the ratio of mass and volume.

Therefore, Density = Mass/ Volume

So, mass of iron piece = Density × Volume

Mass of iron piece , $m= (7.8gcm^{-3})(250cm^{3})$

$m=1950g$

Therefore, the mass of iron piece will be equal to 1950g.