Question

Find the mass of a piece of iron that occupies a volume of 20 cm^3 , given that the density of iron is 8.1 g/cm^3
Options-
1) 16.2 g
2) 1.62 g
3) 162 g
4) 0.162 g
Tell fast pls​

Answer 1

Answer:

m = 162

option 3 is correct

Explanation:

Mass = density × volume

mass = 8.1 g/cm^3 × 20 cm^3

mass = 162 g

Answer 2

Answer:

option 3) 162 g

Explanation:

Given :

Volume of a piece of iron, V = 20 cm³

Density of the iron, ρ = 8.1 g/cm³

To find :

the mass of the piece of iron

Solution :

The density is defined as mass per unit volume.

 $\rm Density =\dfrac{Mass}{Volume}$

$\longmapsto \sf \rho=\dfrac{m}{V}$

Substituting the values,

$\sf 8.1 \ g/cm^3= \dfrac{m}{20 \ cm^3} \\\\ \sf m=8.1 \: g/cm^3 \times 20 \: cm^3\\\\ \sf m=162 \: g$

Therefore, the mass of the piece of iron is 162 g.