Find the mass of Al2O3 that will be formed when 9g of Al burns in 16g of O2.
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from the above equation we can see 4 Al atoms react with 3 molecules of O2 to make 2 molecules of Al2O3
9g Al = ⅓ moles of Al
16 g O2= ½ moles of O2
so here 4(1/12)Al + 3(1/12) O2=> 2(1/6) Al2O3
that means ⅓ moles of Al2O3 will be formed
molar molar mass of aluminium oxide= 102 g
mass of ⅓ moles of Aluminium oxide = 34g
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