find the mass of an ice cube whose sides measure 2 cm . Given density of ice = 900 kg/m3 ?
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Answered by
3
Answer:
Volume of cube = (2cm)^3
= 8cm ^3
density = mass / volume
0.9g /cm^3= mass / 8cm^3
mass = 0.9×8
mass 7.2g
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Explanation:
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Answered by
0
Answer:
Explanation:
Volume : 2*2*2*1/(100*100*100) m^3
Density : 900
Therefore
Mass=Density*Volume =72*10^(-4) kg
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