Question

Find the mass of calcium carbonate that present in100ml of 3M solution

Answer 1

Answer:

30 gms

Explanation:

V=100ml=0.1lit

Molarity=n/V(lit)

3=n/0.1lit

n=0.3 lit

G.M.W of CaCO3=40+12+48=100

n=weight/GMW

0.3=weight/100

weight=0.3×100

weight=30gms