Find the mass of CH3OH produced when 356 gm of CO is mixed with 65.0 gm of
H2
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Answer to Question #106391 in General Chemistry for Logan Benton
Answers>Chemistry>General Chemistry
Question #106391
In the reaction CO(g)+ 2H2(g)-> CH3OH(l)
a. Which reactant is the limiting reactant if 356g of CO and 65.0g of H2 are mixed and allowed to react?
b. How many grams of methanol can be produced from the conditions in part a?
Expert's answer
1. In the reaction
a. Which reactant is the limiting reactant if 356g of CO and 65.0g of H2 are mixed and allowed to react?
b. How many grams of methanol can be produced from the conditions in part a?
Solution:
Step 1 Balance the equation
Step 2 Apply mole concept
molecular weight
hence
Step 3 Compare with given amount of reagents
Answer : Hence CO is limiting reagent
b)
1mole CO produce 1 mole methanol
28g CO produce 32g methanol
356g CO produce 32/28×356 g methanol=406.86g methanol
Answer : 406.86 g Methanol will be produced
Find the mass of CH3OH produced when 356 gm of CO is mixed with 65.0 gm of
H2