Question

Find the mass of Cu deposited at cathode.By passing 6A current through CuSO4 solution for 2 hours?​

Answer 1

mark as brainlist

3 amperes is 5 coulombs per second, 3 C/s

So the total charge in 30 minutes is Q=3C/s×15min×60s/min=2700C

Then the number of moles of copper plated out (n) is:

n=  

zF

Q

​

 

where z is the number of electrons in the half-cell reaction (in this case, 2)

and F is the Faraday constant = 96,485/mol

So, n=  

(2×96485)

2700

​

=0.0139mol

And this is 63.546×0.0139=4.54g

So 4.54 grams are plated deposited at the cathode.