Question

find the mass of each one of the following 1 mole of ethanal​

Answer 1

Answer and Explanation:

$\diamond$ Number of moles is a unit of measurement which is defined as the amount having 6.022 * 10²³ particles

$\diamond$ To find the number of moles we have different formulas

$\diamond$ The following formula gives us the number of moles :

$\boxed{Number \ of \ moles = \dfrac{Given \ mass}{Molar \ mass}}$

$\boxed{Number \ of \ moles = \dfrac{Volume (in \ litres)}{22.4}}$

$\boxed{Number \ of \ moles = \dfrac{Number \ of \ particles}{6.022 * 10^{23}}}$

$\boxed{Number \ of \ moles = Molarity * Volume(in \ litres)}$

$\diamond$ For this question we are using the first equation only

1) 1 mole of water

$\diamond$ Given,

Molar mass of water (H₂O) = 2 + 16

                                            = 18g

Number of moles = 1

$\diamond$ Putting these values in we get,

$\boxed{Number \ of \ moles = \dfrac{Given \ mass}{Molar \ mass}}$

$\implies$ 1 = $\dfrac{Given \ mass}{18}$

$\implies$ Given mass = 1* 18

$\implies$ Given mass = 18 g

2) 1 mole ethanol

$\diamond$ Given,

Molar mass of ethanol (C₂H₅OH) = 24 + 5 + 16 + 1

                                                   = 46g

Number of moles = 1

$\diamond$ Putting these values in we get,

$\boxed{Number \ of \ moles = \dfrac{Given \ mass}{Molar \ mass}}$

$\implies$ 1 = $\dfrac{Given \ mass}{46}$

$\implies$ Given mass = 1 * 46

$\implies$ Given mass = 46g

3) 1 mole glucose

$\diamond$ Given,

Molar mass of glucose (C₆H₁₂O₆) = 72 + 12 + 96

                                                       = 180g

Number of moles = 1

$\diamond$ Putting these values in we get,

$\boxed{Number \ of \ moles = \dfrac{Given \ mass}{Molar \ mass}}$

$\implies$ 1 = $\dfrac{Given \ mass}{180}$

$\implies$ Given mass = 1 * 180

$\implies$ Given mass = 180g

Answer 2

Answer and Explanation:

\diamond⋄ Number of moles is a unit of measurement which is defined as the amount having 6.022 * 10²³ particles

\diamond⋄ To find the number of moles we have different formulas

\diamond⋄ The following formula gives us the number of moles :

\boxed{Number \ of \ moles = \dfrac{Given \ mass}{Molar \ mass}}

Number of moles=

Molar mass

Given mass

\boxed{Number \ of \ moles = \dfrac{Volume (in \ litres)}{22.4}}

Number of moles=

22.4

Volume(in litres)

\boxed{Number \ of \ moles = \dfrac{Number \ of \ particles}{6.022 * 10^{23}}}

Number of moles=

6.022∗10

23

Number of particles

\boxed{Number \ of \ moles = Molarity * Volume(in \ litres)}

Number of moles=Molarity∗Volume(in litres)

\diamond⋄ For this question we are using the first equation only

1) 1 mole of water

\diamond⋄ Given,

Molar mass of water (H₂O) = 2 + 16

= 18g

Number of moles = 1

\diamond⋄ Putting these values in we get,

\boxed{Number \ of \ moles = \dfrac{Given \ mass}{Molar \ mass}}

Number of moles=

Molar mass

Given mass

\implies⟹ 1 = \dfrac{Given \ mass}{18}

18

Given mass

\implies⟹ Given mass = 1* 18

\implies⟹ Given mass = 18 g

2) 1 mole ethanol

\diamond⋄ Given,

Molar mass of ethanol (C₂H₅OH) = 24 + 5 + 16 + 1

= 46g

Number of moles = 1

\diamond⋄ Putting these values in we get,

\boxed{Number \ of \ moles = \dfrac{Given \ mass}{Molar \ mass}}

Number of moles=

Molar mass

Given mass

\implies⟹ 1 = \dfrac{Given \ mass}{46}

46

Given mass

\implies⟹ Given mass = 1 * 46

\implies⟹ Given mass = 46g

3) 1 mole glucose

\diamond⋄ Given,

Molar mass of glucose (C₆H₁₂O₆) = 72 + 12 + 96

= 180g

Number of moles = 1

\diamond⋄ Putting these values in we get,

\boxed{Number \ of \ moles = \dfrac{Given \ mass}{Molar \ mass}}

Number of moles=

Molar mass

Given mass

\implies⟹ 1 = \dfrac{Given \ mass}{180}

180

Given mass

\implies⟹ Given mass = 1 * 180

\implies⟹ Given mass = 180g