Find the mass of ethane (C2H4) gas that has same number of atoms as present in 11 g of CO2. (C:12, H:1)
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Explanation:
Molar mass of carbon dioxide =12+2×16=44 g
Molar mass of O
2
=2×16=32 g
Number of molecules in 32 g oxygen = N
A
Number of molecules in 40 g oxygen =
32
40
×N
A
Given: molecules in 40 g oxygen = molecules of m g carbon dioxide
44
m
×N
A
=
32
40
×N
A
44
m
=
32
40
m=55 g
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