Question

Find the mass of iron obtained by reduction of 640 g fe2o3 assuming 70% yield​

Answer 1

Explanation:

Iron III Oxide is Fe2O3.

The molar mass is 2 x 55.845 + 3 x 16 = 159.69 g/mol

So, the iron is 111.69 / 159.69 = 0.6994 times the mass of Fe2O3.

10kg of iron would require 10/0.6994 = 14.298kg of Fe2O3

Answer 2

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