Question

Find the mass of KNO3 required to produce 126 kg of nitric acid. Find whether a larger or smaller mass of NaNO3 is required for the same purpose.KNO3 + H2SO4 —> KHSO4 + HNO3NaNO3 + H2SO4 —> NaHSO4 + HNO3​

Answer 1

Answer: 1. 202 kg of $KNO_3$

2. A smaller mass of $NaNO_3$ will be required.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{126\times 1000g}{63g/mol}=2000moles$

$KNO_3+H_2SO_4\rightarrow KHSO_4+HNO_3$

According to stochiometry:

1 mole of $HNO_3$ is produced from 1 mole of $KNO_3$

2000 moles of $HNO_3$ is produced from 2000 moles of $KNO_3$

Mass of $KNO_3=moles\times {\text {Molar mass}=2000\times 101=202000g=202kg$

2. $NaNO_3+H_2SO_4\rightarrow KHSO_4+HNO_3$

According to stochiometry:

1 mole of $HNO_3$ is produced from 1 mole of $NaNO_3$

2000 moles of $HNO_3$ is produced from 2000 moles of $NaNO_3$

Mass of $NaNO_3=moles\times {\text {Molar mass}=2000\times 85=1,70,000g=170kg$