Question

Find the mass of koh present in 150cm cube of semi molar aqeous solution

Answer 1

Answer:

Explanation:

1 lt = 1000 cm^3

x lt = 150

x=.15lt

molarity = 0.5 = no. of moles of solute / volume of solution

no. of moles = 1/2 * .15

no. of moles = 0.075

no. of moles = mass / molar mass

0.075 = mass / 52.5 g

mass = 3.92 g