Question

find the mass of koh present in 150cm³ of semimolar aqueous solution
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Answer 1

solution. We have 0.150 liters of solution, since 1 cm3 = 1 milliliter. So we have 0.5 * 0.150 = 0.0750 moles of KOH.

solution. We have 0.150 liters of solution, since 1 cm3 = 1 milliliter. So we have 0.5 * 0.150 = 0.0750 moles of KOH.We need the molar mass of KOH, which is 56.11 g/mol. Multiply moles by molar mass to get the mass of KOH: 0.0750 * 56.11 = 4.21 g KOH.

solution. We have 0.150 liters of solution, since 1 cm3 = 1 milliliter. So we have 0.5 * 0.150 = 0.0750 moles of KOH.We need the molar mass of KOH, which is 56.11 g/mol. Multiply moles by molar mass to get the mass of KOH: 0.0750 * 56.11 = 4.21 g KOH.(I’ve assumed here that the semi-molarity of the solution is exact. If it is only good to 1 significant figure (for example), we should say 4 g KOH.)

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