Chemistry, asked by rohitjogdand17, 10 months ago

Find the mass of KOH present in 150cmcube of semimolar aq solution

Answers

Answered by mishti53

To determine the number of grams of potassium hydroxide, we need to know what is the units of parts per million and what it means. Then, we can multiply the grams of solution to obtain the grams KOH. Parts per million (ppm) means that there is 1 mass unit of solute per 1 million mass units of solution. Therefore,

150 ppm = 150 g KOH / 1000000 g solution

mass KOH = 150 g KOH / 1000000 g solution (1000 g solution)

mass KOH =0.00015 g KOH

rohitjogdand17: Sir can you answer this question with molarity formula

mishti53: Considering 37% as the maximum solubility of HCl, you can calculate themolarity using the solution density (1.2 g/mL) and HCl's molar mass (36.46 g/mol). For 1000 mL of solution, you will have 1200g of weight, of which 37% isHCl: 444g.

mishti53: helped you?

mishti53: or I will find another answer

Answered by mdaarif2004

Answer: 4.27

Explanation:

M=n/v (in L)

1/2= n/0.15=0.075

Then

n =mass/molecular mass

0.075 = x/40+16+1

0.07 = x/57

then

x = 0.075* 57= 4.27

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