Question

find the mass of Na2CO3 present in 150 ml of 3M solution​

Answer 1

Answer:

given volume of na2co3 = 150mL

molecular mass of Na2CO3 = 105g/mol

molarity - 3M

M - given weight/molar weight × 1000/ vol

3 - w/105 × 1000/150

3 = w/ 0.006

w = 3×.006 = . 018

the mass of the compound is 0.018 g

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