find the mass of Na2CO3 required to prepare 250ml of 0.5N solution
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24
hope it will help u......
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it's not molarity it's normality
u shold mension in qs
thanx
according to me molarity ka formula hi applly hoga .....maas to aise hi find hota hai
Answered by
25
N=(w÷GEW)×(1000÷V(ml))
0.5=(w÷53)×(1000÷250)
w=(0.5×53×250)÷1000
w=6.62gr
0.5=(w÷53)×(1000÷250)
w=(0.5×53×250)÷1000
w=6.62gr
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