Find the mass of Na2CO3 which will have the same number of molecules as in 12.3 gm of MgSO4.7H2O
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Answered by
1
Answer:
Number of molecules =(12•3/246)×6•022×10²³
0•05×6•022×10²³
0•3011×10²³
mass=(106×3•01)/60•22
319•06/60•22
5•29
5•3
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Answered by
2
Answer:
Molecular mass of MgSO4. 7H2O is 24+32+64+7(18)=246 gram. No of moles= 12.3/246=0.05moles. As per the question moles of Na2CO3 is 0.05 moles.
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