Chemistry, asked by pravatbehera2009, 9 months ago

find the mass of naoh present in 250 ml of a seminormal solution​

Answers

Answered by shraddha663
2

Answer:

the mass of naoh present in 250 ml of a seminormal solution is 5grams

Explanation:

semi normal solution means , its normality is = N/2

since NaoH has V.f = 1

so, molarity = Normality/v.f = 1/2M

so, moles of NaOH = M*V = 0.5*(0.250l) = 0.125moles

and mass of 0.125moles NaOH = 0.125*40 = 5grams

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