Find the mass of NaOH present in 250 ml of a seminormal solutions
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semi normal solution means , its normality is = N/2
since NaoH has V.f = 1
so, molarity = Normality/v.f = 1/2M
so, moles of NaOH = M*V = 0.5*(0.250l) = 0.125moles
and mass of 0.125moles NaOH = 0.125*40 = 5grams
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