Find the mass of NaOH present in 250ml of a seminormal solution.
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Answered by
1
Answer:
No of moles (n) =
1000
Molarity×V
mL
Given:
M=0.5M
V
mL
=250mL
Therefore, n=
1000
0.5×250
=
1000
125
=0.125mol
Molar mass of NaOH = 40g
Mass of NaOH = 0.125×40=5g
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