Question

find the mass of NaOH required to prepare 0.1M solution in 500cm^3۔?​

Answer 1

Explanation:

Molarity = no. of moles of solute/solution in l

no. of moles of solute = mass / molar mass

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Answer 2

Answer:

2g

Explanation:

molarity : M = n / V ; n = moles ; V : volume (ltr)

molar mass of NaOH : 23 + 16 + 1 = 40g

n = m / molar mass

n = m / 40

500 cm^3 = 500/1000 ltr = 1/2 ltr

now.....M = (m/40) / (1/2) = 0.1

m = 20 × 0.1 = 2

m = 2g