find the mass of nitrogen supplied to soil by 5 kg of urea CO(NH2)2. O= 16, N= 14, C=12, H=1
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molar mass of urea = 16+12+16+16 = 60
% of nitrogen by mass in 1 mole of Urea = 28/60 = 46.66%
now mass of N in 5g urea = 5*(46.66/100) = 2.33g
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