Question

find the mass of Potassium Hydroxide needed to prepare 100 ml 1 molar KOH solution​

Answer 1

Answer:

5.6 grams

Explanation:

we know that,

Formula for molarity, M is

M=w×1000/MM×V(ml), where MM is molar mass.

And molar mass of KOH is 39+16+1=56, M= 1

so,

M= w×1000/56×100

1×56=w×10

56/10=w

5.6 grams =weight which can also be spelled as mass

Answer 2

Answer:

The mass of Potassium Hydroxide needed to prepare 100 ml 1 molar KOH solution​ 0.27 g

Explanation:

Molarity=

(Weight of KOH ÷GMW of KOH) × (1000÷ Vol(ml))

Where GMW = Gram molecular weight

[ Gram molecular weight of KOH= Atomic load of K+ nuclear load of O+ nuclear load of H=10+16+1=27]

⇒0.1=(Weight of KOH ÷27 )× 100 ÷1000

Weight of KOH= 2.7/10

Weight of KOH=0.27 g

Potassium hydroxide:

Potassium hydroxide is an inorganic compound with the recipe KOH, and is regularly called caustic potash.

Alongside sodium hydroxide (NaOH), KOH is a prototypical solid base. It has numerous modern and specialty applications, a large portion of which exploit its burning nature and its reactivity toward acids. An expected 700,000 to 800,000 tons were delivered in 2005. KOH is essential as the forerunner to most delicate and fluid cleansers, as well as various potassium-containing synthetics. A white strong is perilously destructive.

To do more examples on finding the mass of an element visit the links given below:

https://brainly.in/question/21688858

https://brainly.in/question/4190926