Question

find the mass of shotput ,if density is 7.8 gram per centimetre cube ​

Answer 1

Answer:

Given :

Radius of metallic sphere = 4.9 cm

And density of the metal = 7.8 gm / cm³

Volume of sphere = \sf \frac{4} {3}

3

4

π r³

⇒ \sf \frac{4}{3} \times \frac{22}{7} \times 4.9 \times 4.9 \times 4.9

3

4

×

7

22

×4.9×4.9×4.9

⇒ \sf \frac{1479.016} {3}

3

1479.016

cm³

Mass of the shot put = volume × density

⇒ \sf \frac{1479.016} {3} \times 7. 8 gm

3

1479.016

×7.8gm

⇒ 1479.016 × 2.6 gm

⇒ 3845. 44 gm

Hence, Mass of the shot put sphere is 3.845 kg. (approx)

Answer 2

Answer:

Answer :

The mass of the shot put is 3.845 kg.

Step-by-step explanation :

Given :

Radius of metallic sphere = 4.9 cm

And density of the metal = 7.8 gm / cm³

Volume of sphere = \sf \frac{4} {3} π r³

⇒ \sf \frac{4}{3} \times \frac{22}{7} \times 4.9 \times 4.9 \times 4.9

⇒ \sf \frac{1479.016} {3} cm³

Mass of the shot put = volume × density

⇒ \sf \frac{1479.016} {3} \times 7. 8 gm

⇒ 1479.016 × 2.6 gm

⇒ 3845. 44 gm

Hence, Mass of the shot put sphere is 3.845 kg. (approx)