Find the mass of sucrose (Molecular Mass=342) required to be dissolved per 600 cm^3 solution to prepare a semi molar solution.
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Answer:
Explanation:
DepressioninFreezingpointΔT
f
=
M
1
×W
2
W
1
×K
f
×1000
whereW
1
=Weight of Solute
W
2
=Weight of solvent
M
1
=Molar mass of solute
K
f
=Freezing point deprssion constant
Now,ΔT
f
=
342×1000
1.86×68.5×1000
=0.372C
Now,ΔT
f
=T
o
−T
f
So,T
f
=0−0.372=−0.372C.
(Freezing point of purewater=0
0
C.)
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