Physics, asked by marcobaterna, 14 days ago

Find the mass of the other body if a 30kg object is placed within 5 meters and a force of 0.0005 N acts on them.​

Answers

Answered by muruganamutha09
0

Answer:

2000kg

Explanation:

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Answered by talasilavijaya
0

Answer:

The mass of the other is 6.19\times10^{-16}kg.

Explanation:

Given the mass of the object, m=30kg

Let the mass of the other body be M.

Distance of separation, r=5m

The force acting on the object, F=0.0005N=5\times 10^{-4} N

According to Newton's universal law of gravitation, 'the force of attraction F acting between any two bodies of masses m_1~\&~m_2 is directly proportional to the product of their masses and is inversely proportional to the square of the distance r between them'.

F=G\dfrac{m_{1}m_{2}  }{r^{2} }

where G is called the gravitational constant, =6.73\times10^{11} Nm^{2} /kg^{2}

Using the given values in the above formula, we get

5\times 10^{-4} =6.73\times10^{11}\times \dfrac{30\times M}{5^{2} }

Thus the mass of the other body is

M= \dfrac{5\times 10^{-4}\times25}{6.73\times10^{11}\times30}

    =\dfrac{ 10^{-15}\times25}{6.73\times6} =\dfrac{ 10^{-15}\times25}{40.38}

    =0.619\times10^{-15}kg=6.19\times10^{-16}kg

Therefore, the mass of the other is 6.19\times10^{-16}kg.

For more info:

https://brainly.in/question/723725

https://brainly.in/question/3841670

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