Question

Find the mass of the rod as shown in fig above. its center of gravity is 14m from the end A.a)100g b)150gc)80gd)5g

Answer 1

Answer:

i am not sure about this but according to me it should be

let us find the net torque

as Tnet=0    (since its stationary and in rotational equilibrium)

torque by 80gm block + torque by the weight of rod =0

20*80*g-16*m*g=0          (16 cause 30-14=16)

m=100gm

hence mass of rod is 100 gm ie option A

Explanation: