Question

find the mass of water pumped per minute by a motor of power 2hp from the depth of 200m

Answer 1

P=W/t

P=(F x s)/t

1Hp=746W (approx 750 W)

2Hp=1500W

t= 1 min = 60 sec

P=(F x s)/t

F=ma

P= (m x a x s)/t

1500=(m x 10 x 200)/60        [a= g =10m/s^2]

therefore m = 45 kgs