Find the mass present in 85 mile of sodium carbonate mole
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I think the compound is Na2CO3
Given number of moles = 0.85 moles
Molar mass of Na2CO3 = ( 2 x 23 ) + ( 1 x 12 ) + ( 3 x 16 )
= 106 gmol-1
Number of moles = mass / molar mass
So, Mass = Number of moles x Molar mass
= 0.85 moles x 106 gmol-1
= 90.1 g
Therefore mass of Na2CO3 is 90.1 g
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