Question

Find the matrixx&y of [ 2x x/ y 3y] [3/2] =[16/9]

Answer 1

$\sf{\underline{\boxed{\purple{\large{\bold{ Solution}}}}}}$

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$\sf { \left[\begin{array}{cc}2x &x \\y &3y \end{array}\right] \: \: \left[\begin{array}{cc}3\\2\end{array}\right] = \left[\begin{array}{cc}16 \\9\end{array}\right]}$

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$\sf \left[\begin{array}{cc}2x\times 3 &x \times 2 \\y\times 3 &3y\times 2 \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]$

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$\sf \left[\begin{array}{cc}6x & +2x \\3y &+ 6y \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]$

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$\sf \left[\begin{array}{cc}8x \\ 9y \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]$

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Now ;

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8x = 16

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x = 16 / 8

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x = 2

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$\sf{\red{\boxed{\bold{x = 2 }}}}$

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9y = 9

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y = 9/ 9

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y = 1

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$\sf{\red{\boxed{\bold{y = 1}}}}$

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Answer 2

${\huge{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷AnSwEr⫸}}}}}}$

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$\begin{gathered}\sf { \left[\begin{array}{cc}2x &x \\y &3y \end{array}\right] \: \: \left[\begin{array}{cc}3\\2\end{array}\right] = \left[\begin{array}{cc}16 \\9\end{array}\right]}\end{gathered}$

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$\begin{gathered}\sf \left[\begin{array}{cc}2x\times 3 &x \times 2 \\y\times 3 &3y\times 2 \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]\end{gathered}$

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$\begin{gathered}\sf \left[\begin{array}{cc}6x & +2x \\3y &+ 6y \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]\end{gathered}$

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$\begin{gathered}\sf \left[\begin{array}{cc}8x \\ 9y \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]\end{gathered}$

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Now ;

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8x = 16

x = $\frac{16}{8}$

x = 2

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x=2

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9y = 9

y = $\frac{9}{9}$

y = 1

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y=1⠀⠀⠀

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