Math, asked by aoosh09, 8 months ago

find the max and minimum value of 36tan^2 + 49cot^2 +10

Answers

Answered by REDPLANET

1

Answer:

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36tan²∅ + 49cot²∅ + 10

= (6tan∅ + 7 cot∅)² - 74

Max value = -73

Min vakue = -74

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