Question

find the maximum and minimum

Answer 1

minimum value is -2
maximum value is +3x^2 i.e plus three X square


hope this helps pl mark it as brainliest answer

Answer 2

Answer:

Step-by-step explanation:

solving this by maxima and minima

we have y=x^3+3x^2-2

dy/dx=3x^2+6x

put only first derivative = 0

putting first derivative =0 we get

x= -2

take second derivative of y

6x+6

put x= -2

-6

as d^2y/dx^2 less than 0

the y has maximum value at -2

y(-2)=2=maximum value of y

and minimum value for this is not defined