Question

find the maximum and minimum distances from the origin to the curve 5x^2+6xy+5y^2-8=0​

Answer 1

Answer:

4,1

Step-by-step explanation:

(x^2+y^2)+lammda (5x^2+6xy+5y^2_8)

df/dx=2x+lammda (10x+6y)

df/dy=2y+lammda (10y+6x)

equate df/dx and df/dy to 0 then

we get x=y put in above equation

we get max=4,min=1

Answer 2

I want step by step explanation