find the maximum and minimum value if any of the following functions f(X)=(2x-1)²+3
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Answer:
The minimum value is three
Step-by-step explanation:
Gn. f(x) = (2x-1)^2 + 3
f'(x) = 2(2x-1)
putting f'(x) = 0
2(2x-1) = 0
2x-1 = 0
2x = 1
x = 1/2
Finding minimum value,
f(x) = (2x-1)^2 + 3
putting x = 1/2
f(x) = ( 2 × 1/2 - 1 )^2 + 3 = 3
Therefore, minimum value = 3
No maximum value
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