Question

find the maximum and minimum value of 1+4sin²xcos²x

Answer 1

maximum value=5 minimum value=1

Answer 2

Answer:

Step-by-step explanation:

1+4sin^2 xcos^2 x

1+4(sinxcosx)^2

minimum and maximum of (sinxcosx)^n is -1/2^n and 1/2^n for odd

and for even 0 and 1/2^n

here n is even so

minimum

1+4(0)

1

maximum

1+4(1/4)

2

min amd max= 1 and 2