Question

Find the maximum and minimum value of 4-3cosx° .

Answer 1

we know,
maximum value of cosx = 1
so, minimum value of (4 -3cosx) =(4-3×1) =1

minimum value of cosx = -1
so, maximum value of (4 -3cosx)
={ 4 -3×(-1)} = 7

hence 1 and 7 are the minimum and maximum value of ( 4 -3cosx) respectively.

Answer 2

Answer:

Step-by-step explanation:

4-3cosx°

4-3cos pi x/180

for extreme points derivative=0

3pi/180sin pi x/ 180 = 0

sin pi x /180 = 0

sin pi x/180 = sin 0

x=0,pi

double derivative of  4-3cosx°

3pi^2/32400*cos pi x/180

for x=0

d2y/dx2>0

means minimum at x=0

for x=pi

d2y/dx2<0

means maximum at pi

for minimum put x=0

4

for maximum put x=pi

4-3cos(pi^2/180)

1

therefore minimum and maximum=4 and 1