find the maximum and minimum value of cos^2x+cosx+3
Answers
Answered by
0
Answer:
-9/8-minimum value
Explanation:
y=cosx+cox2x
y=cosx+cosx.cosx-1
y=2(cosx.cosx+1/2cosx)-1
=y
2(cosx.cosx+2cosx1/4+1/16-1/16)
y=2(cosx+1/4)the whole square-1/8-1
y=2(cosx+1/4)the whole square-9/8
=-9/8
Similar questions