Question

find the maximum and minimum value of function f(x)=(4\x+2)+x​

Answer 1

f(x)=4x²−4x+4

f(x)=4x²−4x+1+3

∴f(x)=(2x−1)²+3

we have, (2x−1)² ≥0 for all x∈R

⇒(2x−1)²+3≥0+3 for all x∈R

∴f(x)≥3 for all x∈R

∴x=3 is the minimum value.

The function doesn't attain the maximum value at any point in its domain.

Answer 2

Answer:

here is ur answer..hope it will helpu