Question

Find the maximum and minimum value of,sin2x-cos2x​

Answer 1

Answer:

sin3 kon57 max7 bita 9 theta6

Answer 2

Answer:

minimum value = -√2

maximum value = √2

Step-by-step explanation:

MINIMUM VALUE

sin 2x - cos 2x

let say A = sin2x-cos2x

by squaring both sides

• A² = ( sin 2x- cos 2x)²
• A²= sin²2x - cos²2x-2sin2x-2cos2x
• A²= 1-sin4x
• -1 ≤ sin4x≤1
• A²=1-(-1) =2
• A=±√2
• sin4x=1
• A²=0
• A=0

MINIMUM VALUE= -√2

MAXIMUM VALUE= √2

hope it helps you