find the maximum and minimum value of y =pwoer of (x-2) is 6 and pwoer of(x-3)is 5
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Answer:
Step-by-step explanation:
Let P(x, -1) and Q(3, 2) be the given points. Then PQ = 5 (given)
(x−3)
2
+(−1−2)
2
=5
⇒(x−3)
2
+9=25
⇒x=7orx=−1
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