Find the maximum and minimum values of 2x² -15 x² +36x+12
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Answered by
0
Answer:
Correct option is
D
54
f(x)=2x
3
−3x
2
−36x+10
f
′
(x)=6x
2
−6x−36
For maxima or minima,
f
′
(x)=0
⇒x=3,−2
f
′′
(x)=12x−6
f
′′
(3)=30>0 and f
′′
(−2)=−30<0
Hence f(x) has a maximum at x=−2
f(−2)=54
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