Question

Find the maximum and minimum values of 6sinxcosx+4cos2x​

Answer 1

Answer:

maximum value +5 and minimum value -5

Step-by-step explanation:

6sinx coax + 4 cos2x

3*2sinx*cosx+ 4cos2x

3* sin2x + 4 cos2x

°•° 2sinx*cosx = sin2x

now let 2x = ¢

•°• 3sin¢ + 4cos¢

maximum value is √3²+4² = √25 = 5

and minimum value is -√3²+4² = -√25 = -5

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Hope it's helpful

Answer 2

Answer:

refer to this attachment ✅✅