Question

Find the maximum and minimum values of
$f(x) = 4 {x}^{3} - 3 {x}^{2} - 18x + 12$
in the interval of
$( \frac{ - 3}{2} \: \frac{3}{2} )$
only correct span will be reported..​

Answer 1

Answer:

S={x∈R,x

2

+30−11x≤0}

={x∈R,5≤x≤6}

Now f(x)=3x

3

−18x

2

+27x−40

⟹f

′

(x)=9(x−1)(x−3), which is positive in [5,6]

⟹f(x) increasing in [5,6]

Hence maximum value =f(6)=122

Answer 2

Answer:

I have completed it bro