find the maximum area of a rectangular field which is surrounded by a rope of 100m
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Answered by
3
perimeter of rectangle = 2(l+b) =100
l+b = 50 m
l = 50- b
area = l × b
= (50-b) b
= (50b - b^2) m^2
Answered by
9
By taking perimeter of rectangle=2(l+b)=100
l=50-b
area of rectangle=l. B
=(50-b)b
=50b-b^2
By derivative w. R. T b
dA/db=50-2b
dA/db=0
50-2b=0
2b=50
b=25
l=50-b
=50-25=25
hence area =25×25=625m^2
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