Question

find the maximum area that can be enclosed in a triangle of perimeter 24cm​

Answer 1

Answer:

p=

Step-by-step explanation:

a+b+c=24 cm

let a,b,c be x

3x=24 cm

x=24/3

x=8cm

Answer 2

Answer:

16√3cm²

Step-by-step explanation:

equalateral traingle havhighest area from all the traingles.

so, perimeter = 24

p = a + a + a

24 = 3a

24/3 = a

8 = a

side = 8cm

semi perimeter = 24/2 = 12 S = 12

area of traingle = √S(S-a)(S-b)(S-c)

area = √12(12-8)(12-8)(12-8)

area = √4*3(4)(4)(4)

area = 16√3cm²

hence , 16√3cm² is the highest area in 24 cm perimeter of traingle