Question

find the maximum error in measuring the volume of a box of length 24.0 CM breadth 18.6 cm height 6.0 CM

Answer 1

dV/V=dx/x + dy/y +dz/z substitute values
=.05/24+.05/18.6+.05/6.0=0.013104838. Thus dV=0.013104838*24*18.6*6=35.1 cu cm

Answer 2

Answer:

2.6%

Explanation:

Given that,

length =24 cm

width=18.6 cm

height= 6cm

then,

maximum error can be,

$\frac{delta \: v}{v} = \frac{delta \: l}{l } + \frac{delta \: w}{w } + \frac{delta \: h}{h}$

putting the values,

$\frac{delta \: v}{v} = \frac{0.1}{24} + \frac{0.1}{18.6} + \frac{0.1}{6}$

=0.0041+0.0053+0.0166

= 0.026

for percentage, multiply hundred

so,

= 0.026×100

=2.6%

It is the exact answer.

It is the exact answer.please rate me