Find the maximum length of ladder can be placed in a cuboidal room dimensions. 5m×4m×3m
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the maximum length of the ladder will be the length of the diagonal of the cuboid
Diagonal = √( l²+ b²+ h²)
= √ 5²+4²+3²
= √25+16+9
= √50
= 5√2 m
Answered by
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Given, l = 5m , b = 4m , h = 3m
Diagonal = √ l^2 + b^2 + h^2
= √5^2 + 4^2 + 3^2
= √25+ 16 + 9
= √50
= 5√2 ans.
Diagonal = √ l^2 + b^2 + h^2
= √5^2 + 4^2 + 3^2
= √25+ 16 + 9
= √50
= 5√2 ans.
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