find the maximum n minimum distances of the point (1,2,3)from the sphere x^2+y^2+z^2=56
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Answer:
1,2,−1)
x2+y2+z2=24
length = 12+22+(−1)2=1+4+1=6
Now, F(x,y,z,λ)=(x−1)2+(y−2)2+(z+1)2−λ(x2+y2+z2−24)
⇒x2+1−2x+y2+4−4y+z2+1+2z−λx2−λy2−24λ
=(1+λ)x2+(1−λ)y2−2x+1−4y+4+2z+1+(1−λ)z2+24λ
⇒∂x∂F=2x
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