find the maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils...
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Total number of pens = 1001.
Total number pencils = 910.
Maximum number of students among which it can be distributed will be equal to HCF of number of pencils and number of pens.
So HCF of 1001 and 910 -:
Prime factors of the numbers are -
1001 = 7 × 11 × 13
910 = 2 × 5 × 7 × 13
∴ HCF = 7 × 13 = 91.
Hence, 91 students receive same number of pens and pencils.
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